If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-49x-25=0
a = 2; b = -49; c = -25;
Δ = b2-4ac
Δ = -492-4·2·(-25)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-51}{2*2}=\frac{-2}{4} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+51}{2*2}=\frac{100}{4} =25 $
| 8c+17=3(4c-1) | | 8y-7y=23 | | 5–2n=3 | | 4^3x-2=0 | | (4x6+3)+9-2=34 | | 10.9-x=9.89 | | 4-4x=2x8 | | 4-7n=- | | 4^2x-2=0 | | (7x-1)=(4x+5) | | 2s^2-11s-215=0 | | -8x-8+3(X-2)=-3x+3 | | 7(q+3)=107-q | | 4(2x+4)=3x+8 | | 2^3x+1=3^4-x | | 16-r/7=-21 | | -281=11x-6 | | 1=2h–9 | | 2s^2-11s+6=0 | | (x+30)+(2x-5)=180 | | 3+4x+2=2x+21 | | 168=-12(x+12) | | 17-4w=-11 | | u^2-9u-8=0 | | 3(2x+5)=5(X+1 | | -12+2x=-60 | | x^2=11x+30 | | -6q=-5/6 | | (2x+5=20 | | x^2=11x=30 | | 4x-1+x+13=2x+7 | | 2(x-6.00)=8.00 |